document.write( "Question 822152: What is the standard form of 2y^2+4y=3x^2-6x+9, and what are the foci, vertices, center, and asymptotes? \n" ); document.write( "
Algebra.Com's Answer #494949 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the standard form of 2y^2+4y=3x^2-6x+9, and what are the foci, vertices, center, and asymptotes? \n" ); document.write( "*** \n" ); document.write( "2y^2+4y=3x^2-6x+9 \n" ); document.write( "rearrange terms: \n" ); document.write( "3x^2-6x-2y^2-4y=-9 \n" ); document.write( "complete the square: \n" ); document.write( "3(x^2-2x+1)-2(y^2+2y+1)=-9+3-2 \n" ); document.write( "3(x-1)^2-2(y+1)^2=-8 \n" ); document.write( "multiply both sides by -1 \n" ); document.write( "-3(x-1)^2+2(y+1)^2=8 \n" ); document.write( "rearrange terms: \n" ); document.write( "2(y+1)^2-3(x-1)^2=8 \n" ); document.write( " \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form: \n" ); document.write( "For given problem: \n" ); document.write( "center: (1,-1) \n" ); document.write( "a^2=4 \n" ); document.write( "a=2 \n" ); document.write( "vertices: (1,-1±a)=(1,-1±2)=(1,-3) and (1,1) \n" ); document.write( "b^2=8/3 \n" ); document.write( "b=√(8/3)≈√8/√3≈1.633 \n" ); document.write( "c^2=a^2+b^2=4+(8/3)=20/3 \n" ); document.write( "c=√(20/3)≈2.58 \n" ); document.write( "foci: (1,-1±c)=(1,-1±2.58)=(1,-3.58) and (1,1.58) \n" ); document.write( ".. \n" ); document.write( "Aymptotes are straight lines that go through the center (1,-1) \n" ); document.write( "Form of equation: y=mx+b, m=slope, b=y-intercept \n" ); document.write( "slopes of asymptotes for hyperbolas with vertical transverse axis: ±a/b=±2/(√8/√3)=±2√3/√8≈±1.223 \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with positive slope(1.223): \n" ); document.write( "y=1.223x+b \n" ); document.write( "solve for b using coordinates of center \n" ); document.write( "-1=1.223*1+b \n" ); document.write( "b=-2.223 \n" ); document.write( "equation: y=1.223x-2.223 \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with negative slope(-1.223): \n" ); document.write( "y=-1.223x+b \n" ); document.write( "solve for b using coordinates of center \n" ); document.write( "-1=-1.223*1+b \n" ); document.write( "b=0.223 \n" ); document.write( "equation: y=-1.223x+0.223\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |