document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=822455>Question 822455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have another homework question! Here it is \"A slow boat travels across the ocean at 5 miles per hour. A faster boat leaves 4.5 hours after the slower boat traveling 20 miles per hour. How long does it take the fast boat to catch up?\" As much detail as possible please! Thank you all!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #494856 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20060)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=494856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When the fast boat starts out, the slow boat has traveled 4.5 hours at 5 mph.<BR>\n" );
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document.write( "Since d=rt, the slow boat is d=5(4.5)=22.5 miles ahead of the fast boat when the fast boat starts out.<BR>\n" );
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document.write( "The fast boat's catch-up rate is the difference between their speeds or 20-5 or 15 mph.<BR>\n" );
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document.write( "Since t=d/r it will take the fast boat t=22.5/15 or 1.5 hours to catch up the slow boat's 22.5 miles head start.<BR>\n" );
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document.write( "Edwin </SPAN>\n" );
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