document.write( "Question 822339: Five out of 50 people called to give money to a charity actually agrees to give money. Based on this percentage, what is the probability that out of the next 25 people called:
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document.write( "a. At least two agree to give money?
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document.write( "b. At most 5 agree to give money?
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document.write( "c. More than 3 agree to give money?
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Algebra.Com's Answer #494852 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Five out of 50 people called to give money to a charity actually agrees to give money. Based on this percentage, \n" ); document.write( "Binomial Problem with n = 25 ; p(gave) = 1/10 \n" ); document.write( "------------------------------------------------ \r \n" ); document.write( "\n" ); document.write( "what is the probability that out of the next 25 people called: \n" ); document.write( "--------------------- \n" ); document.write( "a. At least two agree to give money? \n" ); document.write( "Ans:: 1 - binomcdf(25,0.1,1) = 0.7288 \n" ); document.write( "------------------------------------- \n" ); document.write( "b. At most 5 agree to give money? \n" ); document.write( "Ans: binomcdf(25,0.1,5) = 0.9666 \n" ); document.write( "------------------------------------------ \n" ); document.write( "c. More than 3 agree to give money? \n" ); document.write( "Ans: 1 - binomcdf(25,0.1,3) = 0.7636 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |