document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69464>Question 69464</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49470 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "what is the SMALLEST positive integer such that when it is divided by 4,by 5, and by 6, it will always leave a remainder of 3?<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "the prime factor form of each of the divisors is<BR>\n" );
document.write( "4=2^2<BR>\n" );
document.write( "5=5<BR>\n" );
document.write( "6=2*3<BR>\n" );
document.write( "The lcm (least common multiple) of these forms is 2^2*5*3=60<BR>\n" );
document.write( "That is the SMALLEST number that 4,5, and 6 divide evenly.<BR>\n" );
document.write( "To have a remainder of 3, add 3 to 60.<BR>\n" );
document.write( "Answer: 63<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );