document.write( "Question 822167: find two numbers whos sum is 21 and whose product is a maximum \n" ); document.write( "
Algebra.Com's Answer #494646 by MathLover1(20850)\"\" \"About 
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Let us assume one of the numbers is \"x\". As the sum of the two numbers is \"21\", the other number is \"21-x\".\r
\n" ); document.write( "\n" ); document.write( "The product of the two numbers is a function \"f%28x%29+=+x%2A%2821-x%29+=+21x-+x%5E2\".\r
\n" ); document.write( "\n" ); document.write( "Now we need to find the \"maximum\" \"+value\" of \"f%28x%29\". \r
\n" ); document.write( "\n" ); document.write( "For this we need the derivative of \"f%28x%29\" and have to equate it to \"0\".\r
\n" ); document.write( "\n" ); document.write( "f’\"%28x%29+=+21+%96+2x+=+0\"\r
\n" ); document.write( "\n" ); document.write( "=> \"10.5+%96+x+=0\"\r
\n" ); document.write( "\n" ); document.write( "=> \"x+=10.5\"\r
\n" ); document.write( "\n" ); document.write( "Now f’’\"%28x%29+=+-2\" which is negative at \"x=10.5\". So \"f+%2810.5%29\" is truly the \"maximum+value\".\r
\n" ); document.write( "\n" ); document.write( "If \"x=10.5\", the first number is \"10.5\" and the second number is \"21-10.5+=+10.5\"\r
\n" ); document.write( "\n" ); document.write( "So the two required numbers are \"10.5\" and \"10.5\"\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-15%2C+35%2C+-10%2C+115%2C+-x%5E2%2B21x%29+\" \r
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