document.write( "Question 821746: how can i make 2 sets of 5 different coins to make 1.85 pound. IF ONE SET IS
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Algebra.Com's Answer #494633 by Edwin McCravy(20063)\"\" \"About 
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document.write( "Answer:  The other set MUST ALSO be 1 pound+50p+20p+10p+5p.\r\n" );
document.write( "You didn't say the second set MUST be different from the\r\n" );
document.write( "first.  :)\r\n" );
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document.write( "There is no other way. If you break any of those 5 coins\r\n" );
document.write( "down into smaller denominations, there will always require more \r\n" );
document.write( "than 5 coins.  There are four ways to make 1.85 pound with 6\r\n" );
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document.write( "1.  (Three 50p)+20p+10p+5p \r\n" );
document.write( "2.  1 pound+(four 20p)+5p\r\n" );
document.write( "3.  1 pound+50p+(three 10p)+5p\r\n" );
document.write( "4.  1 pound+50p+20p+(three 5p)\r\n" );
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document.write( "but as you see, any way you break one of those 5 coins in\r\n" );
document.write( "1 pound+50p+20p+10p+5p down, there will always be more\r\n" );
document.write( "than 5 coins.  Therefore, the other set MUST ALSO be \r\n" );
document.write( "1 pound+50p+20p+10p+5p.\r\n" );
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document.write( "Edwin
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