document.write( "Question 822038: solve for x-values between [0,2pi)
\n" ); document.write( "6sin^2x+9sinx+3=0 \n" ); document.write( "
Algebra.Com's Answer #494591 by lwsshak3(11628)\"\" \"About 
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solve for x-values between [0,2pi)
\n" ); document.write( "6sin^2x+9sinx+3=0
\n" ); document.write( "divide by 3
\n" ); document.write( "2sin^2x+3sinx+1=0
\n" ); document.write( "factor:
\n" ); document.write( "(2sinx+1)(sinx+1)=0
\n" ); document.write( "..
\n" ); document.write( "2sinx+1=0
\n" ); document.write( "sinx=-1/2
\n" ); document.write( "x=5π/4,7π/4 (in quadrant III and IV in which sin>0)
\n" ); document.write( "or
\n" ); document.write( "sinx+1=0
\n" ); document.write( "sinx=-1
\n" ); document.write( "x=3π/2\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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