document.write( "Question 821922: Find the maximum value of the equation: y=-16t^2+80t+2 \n" ); document.write( "
Algebra.Com's Answer #494500 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! Given \n" ); document.write( "(1) -16t^2+80t+2 = 0 which is of the standard quadratic form \n" ); document.write( "(2) ax^2 + bx + c = 0 \n" ); document.write( "If we set (2) equal to f(x) and let \n" ); document.write( "(3) y = f(x) we get \n" ); document.write( "(4) y = ax^2 + bx + c which is also called the formula for a parabola. \n" ); document.write( "You may have learned that the x-axis of symmetry for the parabola is given by \n" ); document.write( "(5) x = -b/2a \n" ); document.write( "In (1) we have a = -16 and b = 80, so we get \n" ); document.write( "(6) x-axis of symmetry = -(80)/(2*(-16)) or \n" ); document.write( "(7) x-axis of symmetry = 80/32 or \n" ); document.write( "(8) x-axis of symmetry = 5/2 \n" ); document.write( "In your problem x = t so we get \n" ); document.write( "(9) t = 5/2 \n" ); document.write( "Another property of the parabola is the it has a maximum or minimum when x (or t in this case) is at the x value of the x-axis of symmetry. Therefore set t=5/2 in (1) to get the maximum or \n" ); document.write( "(10) Max = -16(5/2)^2+80(5/2)+2 or \n" ); document.write( "(11) Max = -16*25/4 + 80*5/2 + 2 or \n" ); document.write( "(12) Max = -100 +200 +2 or \n" ); document.write( "(13) Max = 102 \n" ); document.write( "Answer: The given equation has a maximum value of 102 when t is 5/2. \n" ); document.write( "PS If you are into calculus, you can get (5) by taking the derivative of (4) with respect to x, set this derivative equal to zero and solve for x, or \n" ); document.write( "(14) 2*a*x + b = 0 or \n" ); document.write( "(15) x = -b/2a \n" ); document.write( "All the derivative is, is the slope of the quadratic, and (15) tells us when the slope is zero, i.e a peak or valley. \n" ); document.write( " \n" ); document.write( " |