document.write( "Question 821894: A pilot found that it took 3/4 as long to travel 100 kilometers with a 30 km/hr tailwind as it took to travel the same distance with a 30 km/hr headwind. Find the speed of the plane in still air. \n" ); document.write( "
Algebra.Com's Answer #494492 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A pilot found that it took 3/4 as long to travel 100 kilometers with a 30 km/hr tailwind as it took to travel the same distance with a 30 km/hr headwind. \n" ); document.write( " Find the speed of the plane in still air. \n" ); document.write( ": \n" ); document.write( "Let s = speed of plane in still air \n" ); document.write( "then \n" ); document.write( "(s+30) = effective ground speed with the wind \n" ); document.write( "and \n" ); document.write( "(s-30) = effective ground speed against the wind \n" ); document.write( ": \n" ); document.write( "let d = the one way distance (we don't need to know the distance) \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( "use the decimal equiv of 3/4 \n" ); document.write( ": \n" ); document.write( "with wind time = 3/4 against wind time \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "d(s-30) = .75d(s+30) \n" ); document.write( "divide both sides by d \n" ); document.write( "s-30 = .75(s+30) \n" ); document.write( "s - 30 = .75s + 22.5 \n" ); document.write( "s - .75s = 22.5 + 30 \n" ); document.write( ".25s = 52.5 \n" ); document.write( "s = 52.5/.25 \n" ); document.write( "s = 210 km/h plane speed in still air \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can check this using a distance of 100 km \n" ); document.write( " |