document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=821893>Question 821893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i've never encountered a question about solving the system that involved X^2 and y^2. I'm confused on how to first tackle the problem.\r<BR>\n" );
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document.write( "3y-x=5<BR>\n" );
document.write( "x^2-y^2=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #494491 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=494491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3y-x=5  --> x = 3y - 5<BR>\n" );
document.write( "x^2-y^2=-3<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Sub for x in the 2nd eqn<BR>\n" );
document.write( "(3y-5)^2 - y^2 = -3<BR>\n" );
document.write( "9y^2 - 30y + 25 - y^2 = -3<BR>\n" );
document.write( "8y^2 - 30y + 28 = 0<BR>\n" );
document.write( "4y^2 - 15y + 14 = 0<BR>\n" );
document.write( "(y - 2)*(4y - 7) = 0<BR>\n" );
document.write( "y = 2<BR>\n" );
document.write( "y = 7/4<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Sub and solve for x.<BR>\n" );
document.write( " </SPAN>\n" );
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