document.write( "Question 69429: find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2 \n" ); document.write( "
Algebra.Com's Answer #49441 by funmath(2933)\"\" \"About 
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find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2
\n" ); document.write( "When give a point, (x1,y1), and a slope, m, and asked for an equation of the line, use the point-slope formula, \"highlight%28y-y%5B1%5D=m%28x-x%5B1%5D%29%29\".
\n" ); document.write( "(x1,y1)=(1,-3) and m=-1/2
\n" ); document.write( "\"y-%28-3%29=%28-1%2F2%29%28x-1%29\"
\n" ); document.write( "The standard form of a line is \"highlight%28Ax%2BBy=C%29\", where A, B, and C are integers. Some books require that A be positive.
\n" ); document.write( "\"y%2B3=%28-1%2F2%29%28x-1%29\"
\n" ); document.write( "\"2%28y%2B3%29=2%28-1%2F2%29%28x-1%29\"
\n" ); document.write( "\"2y%2B6=-%28x-1%29\"
\n" ); document.write( "\"2y%2B6=-x%2B1\"
\n" ); document.write( "\"x%2B2y%2B6=x-x%2B1\"
\n" ); document.write( "\"x%2B2y%2B6=1\"
\n" ); document.write( "\"x%2B2y%2B6-6=1-6\"
\n" ); document.write( "\"highlight%28x%2B2y=-5%29\"
\n" ); document.write( "Happy Calculating!!!
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