document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=821654>Question 821654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 3cm longer than it is wide. the diagonal is 15 cm. find the dimensions of the rectangle. use quadratic formula </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #494304 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=494304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 3cm longer than it is wide. the diagonal is 15 cm. find the dimensions of the rectangle. use quadratic formula<BR>\n" );
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document.write( "width = x cm<BR>\n" );
document.write( "length = x+3 cm<BR>\n" );
document.write( "diag = 15 cm<BR>\n" );
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document.write( "Use Pythgoras:<BR>\n" );
document.write( "x^2 + (x+3)^2 = 15^2<BR>\n" );
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document.write( "x^2 + x^2 + 6x + 9 = 225<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "2x^2 + 6x - 216 = 0<BR>\n" );
document.write( "x^2 + 3x - 108 = 0<BR>\n" );
document.write( "(x-9)(x+12) = 0<BR>\n" );
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document.write( "Positive solution:<BR>\n" );
document.write( "x = 9 cm (width)<BR>\n" );
document.write( "x+3 = 12 cm (width)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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