document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=9180>Question 9180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find a vertex angle for a regular octagon? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4943 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you need to find the sum of all the angles within a regular octagon.  To do this, draw an octagon (8 sides, like a stop sign!), select a vertex (any vertex will do!), and draw diagonals from that vertex to each other vertex in the octagon.  These diagonal will divide the octagon into 6 triangles (it's always 2 less than the number of sides in the figure being \"diagonalized\").  Each triangle has 180 degrees, which multiplied times 6 gives you 1080 degrees.  This 1080 degrees represents the sum of the 8 vertex angles of the octagon.  To find the size of each angle, divide 1080 by 8, or 135 degrees.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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