document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=821471>Question 821471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 4 less than three times the second number. their total is 64. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #494146 by </B><A HREF=/tutors/aboutme.mpl?userid=balthazar612><B>balthazar612(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=balthazar612><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=494146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let numbers x and y<BR>\n" );
document.write( " 3x-y=4<BR>\n" );
document.write( "  X+y=64<BR>\n" );
document.write( "Y is cancelled by adding both equations<BR>\n" );
document.write( " 4x= 68<BR>\n" );
document.write( " X= 68/4<BR>\n" );
document.write( "X = 17<BR>\n" );
document.write( "Putting value of x in equation 1<BR>\n" );
document.write( " 4x-y=4<BR>\n" );
document.write( " 4*17 -y = 4<BR>\n" );
document.write( " 68- y = 4<BR>\n" );
document.write( "Y = 68 -4<BR>\n" );
document.write( " Y = 64<BR>\n" );
document.write( "So numbers are 17 and 64 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );