document.write( "Question 821334: the distance between two cities is one hundred miles, a woman drives from one city to the other at a rate of fifty mph. At what rate must she return if the total is three hours and forty minutes? \n" ); document.write( "
Algebra.Com's Answer #494142 by TimothyLamb(4379)\"\" \"About 
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\n" ); document.write( "s = d / t
\n" ); document.write( "t = d / s
\n" ); document.write( "---
\n" ); document.write( "out:
\n" ); document.write( "t = d / s
\n" ); document.write( "x = 100 / 50 = 2 hours
\n" ); document.write( "---
\n" ); document.write( "return:
\n" ); document.write( "t = d / s
\n" ); document.write( "y = 100/s
\n" ); document.write( "---
\n" ); document.write( "round trip time:
\n" ); document.write( "3 + 40/60 = 3.666666 hours
\n" ); document.write( "3 + 2/3
\n" ); document.write( "9/3 + 2/3
\n" ); document.write( "11/3 = 3.666666 hours
\n" ); document.write( "---
\n" ); document.write( "x + y = 11/3
\n" ); document.write( "2 + 100/s = 11/3
\n" ); document.write( "100/s = 11/3 - 2
\n" ); document.write( "100/s = 11/3 - 6/3
\n" ); document.write( "100/s = 5/3
\n" ); document.write( "s = 100(3/5)
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "s = 60 mph
\n" ); document.write( "---
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