document.write( "Question 821438: Find cos2x,sin2x , and tan2x if sinx=-12/13 and x terminates in quadrant IV . \n" ); document.write( "
Algebra.Com's Answer #494141 by lwsshak3(11628)\"\" \"About 
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Find cos2x,sin2x , and tan2x if sinx=-12/13 and x terminates in quadrant IV .
\n" ); document.write( "Identities:
\n" ); document.write( "cos2x=cos^2x-sin^2x
\n" ); document.write( "sin2x=2sinxcosx
\n" ); document.write( "tan2x=(2tanx)/(1-tan^2x)
\n" ); document.write( "..
\n" ); document.write( "sinx=-12/13
\n" ); document.write( "you are working with a (5-12-13) reference right triangle in quadrant IV where sin<0,cos>0,tan<0
\n" ); document.write( "..
\n" ); document.write( "sinx=-12/13 (given)
\n" ); document.write( "cosx=5/13
\n" ); document.write( "tanx=-12/5
\n" ); document.write( "..
\n" ); document.write( "cos2x=cos^2x-sin^2x=25/169-144/69=-119/169
\n" ); document.write( "sin2x=2sinxcosx=2*(-12/13)*(5/13)=-120/169
\n" ); document.write( "tan2x=(2tanx)/(1-tan^2x)
\n" ); document.write( "=2(-12/5)/(1-(144/25))=(-24/5)/(-119/25)=(-24/5)(25/119)=120/119
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