document.write( "Question 821438: Find cos2x,sin2x , and tan2x if sinx=-12/13 and x terminates in quadrant IV . \n" ); document.write( "
Algebra.Com's Answer #494141 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find cos2x,sin2x , and tan2x if sinx=-12/13 and x terminates in quadrant IV . \n" ); document.write( "Identities: \n" ); document.write( "cos2x=cos^2x-sin^2x \n" ); document.write( "sin2x=2sinxcosx \n" ); document.write( "tan2x=(2tanx)/(1-tan^2x) \n" ); document.write( ".. \n" ); document.write( "sinx=-12/13 \n" ); document.write( "you are working with a (5-12-13) reference right triangle in quadrant IV where sin<0,cos>0,tan<0 \n" ); document.write( ".. \n" ); document.write( "sinx=-12/13 (given) \n" ); document.write( "cosx=5/13 \n" ); document.write( "tanx=-12/5 \n" ); document.write( ".. \n" ); document.write( "cos2x=cos^2x-sin^2x=25/169-144/69=-119/169 \n" ); document.write( "sin2x=2sinxcosx=2*(-12/13)*(5/13)=-120/169 \n" ); document.write( "tan2x=(2tanx)/(1-tan^2x) \n" ); document.write( "=2(-12/5)/(1-(144/25))=(-24/5)/(-119/25)=(-24/5)(25/119)=120/119 \n" ); document.write( " \n" ); document.write( " |