document.write( "Question 821332: A grocer mixed cashews worth $4.25 per pound with peanuts worth $2.75 per pound. How many pounds of each kind did he use to make a mixture of 60 pounds to sell at $3.75 per pound? \n" ); document.write( "
Algebra.Com's Answer #494034 by stanbon(75887)\"\" \"About 
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A grocer mixed cashews worth $4.25 per pound with peanuts worth $2.75 per pound. How many pounds of each kind did he use to make a mixture of 60 pounds to sell at $3.75 per pound?
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\n" ); document.write( "Quantity:: c + p = 60 lbs
\n" ); document.write( "Value::: 4.25c + 2.75p = 3.75*60
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\n" ); document.write( "Modify for elimination:
\n" ); document.write( "425c + 425p = 425*60
\n" ); document.write( "425c + 275p = 375*60
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\n" ); document.write( "Subtract and solve for \"p\"::
\n" ); document.write( "150p = 50*60
\n" ); document.write( "p = 20 lbs (amt. of peanuts needed)
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\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "c + p = 60 lbs
\n" ); document.write( "c = 40 lbs (amt. of cashews needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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