document.write( "Question 821297: \"The product of two consecutive integer is 80 more than 15 times the larger integer.\" What do I do to solve this problem? \n" ); document.write( "
Algebra.Com's Answer #494004 by rothauserc(4718)\"\" \"About 
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let x and x+1 be the consecutive integers, then
\n" ); document.write( "x * (x+1) = 15 * (x+1) + 80
\n" ); document.write( "x^2 + x = 15x + 15 + 80
\n" ); document.write( "x^2 -14x -95 = 0
\n" ); document.write( "this quadratic factors into
\n" ); document.write( "(x-19) * (x+5) = 0 and
\n" ); document.write( "x = 19 or -5
\n" ); document.write( "there fore we have two sets of solutions
\n" ); document.write( "solution set 1 is 19 and 20
\n" ); document.write( "solution set 2 is -5 and -4
\n" ); document.write( "let's check the solutions
\n" ); document.write( "19*20 = 15*20 + 80
\n" ); document.write( "380 = 300 + 80
\n" ); document.write( "380 = 380
\n" ); document.write( "solution set 1 checks
\n" ); document.write( "-5*-4 = 15 * (-4) + 80
\n" ); document.write( "20 = -60 + 80
\n" ); document.write( "20 = 20
\n" ); document.write( "solution set 2 checks\r
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