document.write( "Question 821193: Find the sum of the first 60 terms of the sequence below.
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document.write( "15,17,2,-15,-17
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document.write( "(Where and n is less than or equal to 3.) \n" );
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Algebra.Com's Answer #493970 by KMST(5328)![]() ![]() You can put this solution on YOUR website! It is \n" ); document.write( "The first term is \n" ); document.write( "The second term is \n" ); document.write( "The formula given to calculate each term starting with the third term, \n" ); document.write( " \n" ); document.write( "So for \n" ); document.write( "for \n" ); document.write( "for \n" ); document.write( " \n" ); document.write( "If you look very closely, or if you calculate a few more terms beyond the 5 terms given, you realize that you are sort of going around in circles. \n" ); document.write( "You will see that \n" ); document.write( "Have you ever read the book Hopscotch by Julio Cortázar? \n" ); document.write( "You could try your algebra to prove that \n" ); document.write( "The ordered set of the first 6 terms is \n" ); document.write( "the same as \n" ); document.write( "the ordered set of the next 6 terms, \n" ); document.write( "the same as \n" ); document.write( "the ordered set of the next 6 terms, \n" ); document.write( "and so on. \n" ); document.write( "The first six terms, 15,17,2,-15,-17,-2, add up to 0. \n" ); document.write( "So do terms number 7 through 12, \n" ); document.write( "and terms number 13 through 18, \n" ); document.write( "and so on. \n" ); document.write( "In general if you start with the first term, and add all the terms up to a term number \n" ); document.write( "you will be adding packets of 6 terms that add up to 0, \n" ); document.write( "and if \n" ); document.write( "you will add a few more terms at the end. \n" ); document.write( "How many terms are you adding at the end? \n" ); document.write( "The remainder of dividing the number \n" ); document.write( " \n" ); document.write( "NOTE: \n" ); document.write( "Good try at using the symbols from this site. \n" ); document.write( "For subscripts, we wrap the subscript in square brackets, as in a[n] for \n" ); document.write( "For greater than or equal to, we use >= . \n" ); document.write( "For not equal to, we use <> . \n" ); document.write( " |