document.write( "Question 821209: 2sin^2xcosx - cosx = 0 solve on the interval [0,2pi] \n" ); document.write( "
Algebra.Com's Answer #493959 by lwsshak3(11628)\"\" \"About 
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2sin^2xcosx - cosx = 0 solve on the interval [0,2pi]
\n" ); document.write( "cosx(2sin^2x-1)=0
\n" ); document.write( "..
\n" ); document.write( "cosx=0
\n" ); document.write( "x=π/2, 3π/2
\n" ); document.write( "or
\n" ); document.write( "2sin^2x-1=0
\n" ); document.write( "sin^2x=1/2
\n" ); document.write( "sinx=±√(1/2)=±√2/2
\n" ); document.write( "x=π/4, 3π/4, 5π/4, 7π/4
\n" ); document.write( " \n" ); document.write( "
\n" );