document.write( "Question 821210: sinx + cosx =sqrt2 (solve on the interval [0,2pi]
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Algebra.Com's Answer #493958 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! sinx + cosx =sqrt2 (solve on the interval [0,2pi] \n" ); document.write( "try x=π/4 \n" ); document.write( "sin(π/4)+cos(π/4)=√2/2+√2/2=2√2/2=√2 \n" ); document.write( "so, x=π/4 \n" ); document.write( " |