document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=821024>Question 821024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a triangle is 52m and the sides are 2x, x+7, and 3(x-1), how do I find the value of the xs? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #493849 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=493849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Add up the sides and set them equal to the perimeter. Then solve for x.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "S1 + S2 + S3 = P\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2x + (x+7) + 3(x-1) = 52\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2x+x+7+3x-3 = 52\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "6x+4 = 52\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "6x = 52-4\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "6x = 48\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (48)/(6)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = <font color=\"red\">8</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );