document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=821023>Question 821023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 10 feet longer than the width. if the perimeter is 104 feet find the length and width of the rectangle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #493845 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=493845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 10 feet longer than the width. if the perimeter is 104 feet find the length and width of the rectangle<BR>\n" );
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document.write( "Let the width be \"w\";<BR>\n" );
document.write( "Then the length is \"w+10\"<BR>\n" );
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document.write( "Perimeter = 2(width + length)<BR>\n" );
document.write( "104 = 2(w + w+10)<BR>\n" );
document.write( "52 = 2w + 10<BR>\n" );
document.write( "2w = 42<BR>\n" );
document.write( "width = 21 ft.<BR>\n" );
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document.write( "length = w +10 = 31 ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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