document.write( "Question 820931: factor 4x^2-289 \n" ); document.write( "
Algebra.Com's Answer #493767 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "4x^2-289 = (2x-17)(2x+17) Note: \"17%2A17+=+289\"
\n" ); document.write( "Use FOIL to check factoring
\n" ); document.write( "F First terms
\n" ); document.write( "O Outside terms
\n" ); document.write( "I Inside terms
\n" ); document.write( "L Last terms
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