document.write( "Question 820926: the length of a rectangle is 5 more than the width. if the perimeter is 42 ft, what are the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #493764 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "the length of a rectangle is 5 more than the width . length is ((x+5)
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document.write( "if the perimeter is 42 ft, what are the dimensions of the rectangle.
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document.write( " P = 2(x+5) + 2x = 42ft
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document.write( "      2x + 10 + 2x = 42ft
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document.write( "           4x = 32ft
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document.write( "            x = 8ft, the width.  The length is 13ft
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document.write( "CHECKING our answer***
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document.write( "  26ft + 16ft = 42ft \n" );
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