document.write( "Question 820859: Please help me answer the equation:\r
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Algebra.Com's Answer #493742 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "log(x+3)=1-logx     |Note:  x > 0
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document.write( "log(x+3) + logx = 1
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document.write( "log x(x+3)= 1
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document.write( "   x(x+3) = 10^1
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document.write( "   x^2 + 3x - 10 = 0
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document.write( "  (x+5)(x-2) = 0  x = 2 (tossing out negative solution as x must be >0
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document.write( "CHECKING our answer***
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document.write( " log 2*5 = 1
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