document.write( "Question 820715: Log subscript 12 ( v squared +35) = log subscript 12 (-12v -1) \n" ); document.write( "
Algebra.Com's Answer #493703 by lwsshak3(11628)\"\" \"About 
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Log subscript 12 ( v squared +35) = log subscript 12 (-12v -1)
\n" ); document.write( "\"log%2812%2C%28v%5E2%2B35%29%29=log%2812%2C%28-12v-1%29%29\"
\n" ); document.write( "\"log%2812%2C%28v%5E2%2B35%29%29-log%2812%2C%28-12v-1%29%29=0\"
\n" ); document.write( "\"log%2812%2C%28v%5E2%2B35%29%2F%28-12v-1%29%29=0\"
\n" ); document.write( "convert to exponential form: base(12) raised to log of number (0)=(v^2+35)/(-12v-1)
\n" ); document.write( "12^0=(v^2+35)/(-12v-1)
\n" ); document.write( "(v^2+35)/(-12v-1)=1
\n" ); document.write( "v^2+35=-12v-1
\n" ); document.write( "v^2+12v+36=0
\n" ); document.write( "(v+6)^2=0
\n" ); document.write( "v=-6(multiplicity 2)\r
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