document.write( "Question 820740: Two trains are 339 miles apart, and their speeds differ by 25 mph. Find the speed of each train if they are traveling toward each other and will meet in 3 hours \n" ); document.write( "
Algebra.Com's Answer #493699 by josmiceli(19441)\"\" \"About 
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Think of one train as standing still and the other
\n" ); document.write( "approaching at the sum of their speeds
\n" ); document.write( "Let \"+s+\" = the speed of the slower train in mi/hr
\n" ); document.write( "\"+s+%2B+25+\" = the speed of the faster train in mi/hr
\n" ); document.write( "------------------
\n" ); document.write( "\"+339+=+%28+s+%2B+s+%2B+25+%29%2A3+\"
\n" ); document.write( "\"+339+=+%28+2s+%2B+25+%29%2A3+\"
\n" ); document.write( "\"+339+=+6s+%2B+75+\"
\n" ); document.write( "\"+6s+=+264+\"
\n" ); document.write( "\"+s+=+44+\"
\n" ); document.write( "\"+s+%2B+25+=+69+\"
\n" ); document.write( "The speed of the slower train is 44 mi/hr
\n" ); document.write( "The speed of the faster train is 69 mi/hr
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "Equation for slower train:
\n" ); document.write( "\"+d%5B1%5D+=+44%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+132+\" mi
\n" ); document.write( "Equation for faster train:
\n" ); document.write( "\"+d%5B2%5D+=+69%2A3+\"
\n" ); document.write( "\"+d%5B2%5D+=+207+\" mi
\n" ); document.write( "--------------
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+132+%2B+207+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+339+\" mi
\n" ); document.write( "OK
\n" ); document.write( "
\n" );