document.write( "Question 820690: Patty and Toby live 345 miles apart. They decide to drive to meet one another. Patty leaves at noon traveling at an average rate of 45 mph and Toby leaves at 3:00 pm traveling at an average speed of 60 mph. At what time will they meet? \n" ); document.write( "
Algebra.Com's Answer #493687 by mananth(16946)\"\" \"About 
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Patty 45 mph 12:00 PM
\n" ); document.write( "Toby 60 mph 03:00 PM 3 hours late
\n" ); document.write( "Distance 345 miles
\n" ); document.write( "In 3 hours Patty travels 135 miles before Toby starts
\n" ); document.write( "So distance = 210 before Toby starts
\n" ); document.write( "Let time they take to meet be x hours
\n" ); document.write( "Patty distance traveled 45 x miles
\n" ); document.write( "Toby distance traveled 60 x miles
\n" ); document.write( "t=d/r
\n" ); document.write( "combined speed= 105 mph
\n" ); document.write( "
\n" ); document.write( "105 x = 210
\n" ); document.write( "x= 2.00 hours \r
\n" ); document.write( "\n" ); document.write( "They will meet at 5.00 PM
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