document.write( "Question 820619: how do i find the asymptotes for (y^2/16)-(x^2/81)=1 \n" ); document.write( "
Algebra.Com's Answer #493639 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how do i find the asymptotes for \n" ); document.write( "(y^2/16)-(x^2/81)=1 \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form of equation: \n" ); document.write( ".. \n" ); document.write( "Asymptotes of hyperbolas are straight-line equations that go through the center. \n" ); document.write( "Their standard form: y=mx+b, m=slope, b=y-intercept \n" ); document.write( "slopes of hyperbolas with vertical transverse axis=±a/b \n" ); document.write( "slopes of hyperbolas with horizontal transverse axis=±b/a \n" ); document.write( ".. \n" ); document.write( "For given hyperbola: \n" ); document.write( "center: (0,0) \n" ); document.write( "a^2=16 \n" ); document.write( "a=√16=4 \n" ); document.write( "b^2=81 \n" ); document.write( "b=√81=9 \n" ); document.write( "slopes of asymptotes=±a/b=±4/9 \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with positive slope: \n" ); document.write( "y=(4/9)x+b \n" ); document.write( "solve for b using coordinates of center: \n" ); document.write( "b=y-intercept=0 \n" ); document.write( "equation: y=4x/9 \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with negative slope: \n" ); document.write( "y=(-4/9)x+b \n" ); document.write( "b=0 \n" ); document.write( "equation:y=-4x/9 \n" ); document.write( " |