document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=820396>Question 820396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In an examination 10 questions are to be answered choosing at least 4 from each of part A and part B. If there are 6 <BR>\n" );
document.write( "questions in part A and 7 in part B, in how many ways can 10 questions be answered ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #493504 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=493504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  In an examination 10 questions are to be answered choosing at least 4 from each of part A and part B. \r<BR>\n" );
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document.write( "If there are 6 questions in part A and 7 in part B, in how many ways can 10 questions be answered ?<BR>\n" );
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document.write( "Combinations from A and from B:: 4/6 ; 5/5 ; 6/4<BR>\n" );
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document.write( "# of ways to get the 4/6 pattern: 6C4*7C6 = 15*7 = 105<BR>\n" );
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document.write( "# of ways to get the 5/5 pattern: 6C5*7C5 = 6*21 = 126<BR>\n" );
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document.write( "# of ways to get the 6/4 pattern: 6C6*7C4 = 1*35 = 35<BR>\n" );
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document.write( "Total # of ways: 266<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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