document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=820273>Question 820273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 65. one number is five more than a second number. it is also twice the third. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #493454 by </B><A HREF=/tutors/aboutme.mpl?userid=Alpha+Maximus><B>Alpha Maximus(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alpha+Maximus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alpha+Maximus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=493454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the 3 numbers be 'a' , 'b' and 'c' respectively and let 'a' be the largest number. Thus, we have that:<BR>\n" );
document.write( "a+b+c=65.......(1)<BR>\n" );
document.write( "a=b+5...........(2)<BR>\n" );
document.write( "a=2c.............(3)<BR>\n" );
document.write( "Thus, we have that: b=a-5(from 2) and c=0.5a<BR>\n" );
document.write( "Substituting the alternate values of b and c(in terms of a) respectively into (1), we have:<BR>\n" );
document.write( "a+(a-5)+0.5a=65<BR>\n" );
document.write( "a+a-5+0.5a=65<BR>\n" );
document.write( "2.5a=70<BR>\n" );
document.write( "a=70/2.5=28<BR>\n" );
document.write( "Thus, b=a-5=28-5=23 and c=0.5a=0.5*28=14<BR>\n" );
document.write( "Therefore the numbers are 28, 23 and 14. Taadaa! :D </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );