document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69305>Question 69305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One solution of 2x^2+11x+k=0 is -5. Find the other solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49344 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One solution of 2x^2+11x+k=0 is -5. Find the other solution.<BR>\n" );
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document.write( "Here's one way.<BR>\n" );
document.write( "Use synthetic division:<BR>\n" );
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document.write( "-5 | 2 + 11 + k<BR>\n" );
document.write( "..............-10 - 5<BR>\n" );
document.write( ".....--------------<BR>\n" );
document.write( "..........2...+1 + 0<BR>\n" );
document.write( "Which is (2x + 1) is the other solution<BR>\n" );
document.write( ":<BR>\n" );
document.write( "We know there is no remainder so: k - 5 = 0; k = +5<BR>\n" );
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document.write( "FOIL (x+5)(2x + 1) = 2x^2 + 11x + 5 to check it: </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );