document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=820239>Question 820239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me <BR>\n" );
document.write( "The width of a rectangle is 9 feet less than its length. The area of the rectangle is 90 ft^ . Find the length and width.<BR>\n" );
document.write( "Please help me I wasn't here on the day they taught us this. Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #493437 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=493437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 9 feet less than its length. The area of the rectangle is 90 ft^ . Find the length and width.<BR>\n" );
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document.write( "90 = W*L = W*(W + 9)<BR>\n" );
document.write( "W^2 + 9W - 90 = 0<BR>\n" );
document.write( "(W-6)*(W+15 = 0<BR>\n" );
document.write( "W = 6<BR>\n" );
document.write( "L = 15<BR>\n" );
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document.write( "Or try pairs of factors of 90<BR>\n" );
document.write( "1*90<BR>\n" );
document.write( "2*45<BR>\n" );
document.write( "3*30<BR>\n" );
document.write( "etc, until you find 2 that differ by 9<BR>\n" );
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