document.write( "Question 820200: A cargo plane flew to the maintenance
\n" ); document.write( "facility and back. It took one hour less time
\n" ); document.write( "to get there than it did to get back. The
\n" ); document.write( "average speed on the trip there was 220
\n" ); document.write( "mph. The average speed on the way back
\n" ); document.write( "was 200 mph. How many hours did the trip
\n" ); document.write( "there take?
\n" ); document.write( "

Algebra.Com's Answer #493427 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A cargo plane flew to the maintenance facility and back.
\n" ); document.write( "It took one hour less time to get there than it did to get back.
\n" ); document.write( " The average speed on the trip there was 220 mph.
\n" ); document.write( " The average speed on the way back was 200 mph.
\n" ); document.write( " How many hours did the trip there take?
\n" ); document.write( ":
\n" ); document.write( "Let t = time to get there
\n" ); document.write( "then
\n" ); document.write( "(t+1) = time to get back
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: dist = speed * time
\n" ); document.write( "dist there = dist back
\n" ); document.write( "220t = 200(t+1)
\n" ); document.write( "220t = 200t + 200
\n" ); document.write( "220t - 200t = 200
\n" ); document.write( "20t = 200
\n" ); document.write( "t = 200/20
\n" ); document.write( "t = 10 hrs to get there
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the distance each way, they should be equal if we did it right
\n" ); document.write( "220 * 10 = 2200 miles
\n" ); document.write( "200 * 11 = 2200 miles
\n" ); document.write( "
\n" );