document.write( "Question 820133: Two trains leave two cities that are 310 km apart, traveling toward each other on parallel tracks. One train travels at 70 kph and the other travels at 90 kph. If the slower train leaves at 9:40 a.m. and the faster train leaves at 11:00 a.m., at what time will they pass each other? Round the answer to the nearest minute. \n" ); document.write( "
Algebra.Com's Answer #493422 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The time of the slower train's head start is \n" ); document.write( "11:00 AM minus 9:40 AM = 1 hour 20 minutes \n" ); document.write( "------------ \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------- \n" ); document.write( "Start a stopwatch when the faster train leaves \n" ); document.write( "Let \n" ); document.write( "the trains meet \n" ); document.write( "Let \n" ); document.write( "until they meet \n" ); document.write( "--------------- \n" ); document.write( "Faster train's equation: \n" ); document.write( "(1) \n" ); document.write( "Slower train's equation: \n" ); document.write( "(2) \n" ); document.write( "Substitute (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "This is the time after 11:00 AM when they meet \n" ); document.write( " \n" ); document.write( "-------------------- \n" ); document.write( "They will meet at about 12:21 PM \n" ); document.write( "----------- \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "error may be due to rounding off\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |