document.write( "Question 820173: At 9:00 am a truck leaves the yard traveling west at a rate of 40 mph. At 11:00 am a second truck leaves along the same route, traveling at 50mph. When will the second truck catch up to the first?
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Algebra.Com's Answer #493419 by TimothyLamb(4379)\"\" \"About 
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head start:
\n" ); document.write( "s = d / t
\n" ); document.write( "d = s * t
\n" ); document.write( "d = 40 / (11 - 9)
\n" ); document.write( "d = 20 miles
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\n" ); document.write( "when the trucks meet they will both be distance D from the yard
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\n" ); document.write( "first truck:
\n" ); document.write( "D = 40(t + 2)
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\n" ); document.write( "second truck:
\n" ); document.write( "D = 50t
\n" ); document.write( "---
\n" ); document.write( "D = 40(t + 2) = 50t
\n" ); document.write( "40t + 80 = 50t
\n" ); document.write( "10t = 80
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\n" ); document.write( "t = 8
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\n" ); document.write( "answer:
\n" ); document.write( "the trucks will meet at:
\n" ); document.write( "11 + 8
\n" ); document.write( "19:00 or 7:00 PM
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