document.write( "Question 820173: At 9:00 am a truck leaves the yard traveling west at a rate of 40 mph. At 11:00 am a second truck leaves along the same route, traveling at 50mph. When will the second truck catch up to the first?
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Algebra.Com's Answer #493417 by stanbon(75887)\"\" \"About 
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At 9:00 am a truck leaves the yard traveling west at a rate of 40 mph. At 11:00 am a second truck leaves along the same route, traveling at 50mph. When will the second truck catch up to the first?
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\n" ); document.write( "1st truck DATA:
\n" ); document.write( "rate = 40 mph ; time = x hrs ; distance = r*t = 40x miles
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\n" ); document.write( "2nd truck DATA:
\n" ); document.write( "rate = 50 mph ; time = x-2 hrs ; distance = r*t = 50(x-2) miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "40x = 50x-100
\n" ); document.write( "10x = 100
\n" ); document.write( "x = 10 hrs
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\n" ); document.write( "Meeting time:: 9:00AM + 10 hrs = 7:00PM
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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