document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=820081>Question 820081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a mean average of 60 on seven exam is needed to pass a course. on her first exams, paula received grades 51, 72, 80, 62, 57, and 69\r<BR>\n" );
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document.write( "what grade must she receive on her last exam to pass the course?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #493387 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=493387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 51, 72, 80, 62, 57, and 69 add up to 391<BR>\n" );
document.write( "-9+12+20+2-3+9=+31<BR>\n" );
document.write( "391-360=31<BR>\n" );
document.write( "6*60=360 so you are 31 over the average of sixty<BR>\n" );
document.write( "so you need only 60-31=29\r<BR>\n" );
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document.write( "(391+x)/7>=60<BR>\n" );
document.write( "x>=29<BR>\n" );
document.write( "Wow </SPAN>\n" );
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