document.write( "Question 820003: 2logx log5=log15 log2x I have no idea what I am doing, so some help would be nice please and thank you \n" ); document.write( "
Algebra.Com's Answer #493379 by ortarico(23)![]() ![]() ![]() You can put this solution on YOUR website! ------------\r \n" ); document.write( "\n" ); document.write( "2logx log5 = log15 log2x \n" ); document.write( "logx^2 log5 = log15 log2x \n" ); document.write( "logx^2 - log2x = log15 - log5 \n" ); document.write( "--------------\r \n" ); document.write( "\n" ); document.write( "From law of log: LogA_c - LogB_c = Log_c (A/B)\r \n" ); document.write( "\n" ); document.write( ":. Log x^2/2x = Log 15/5 \n" ); document.write( "Log x/2 = Log 3\r \n" ); document.write( "\n" ); document.write( "Log with Log cancel: \n" ); document.write( "x/2 = 3 \n" ); document.write( "x = 6 \n" ); document.write( " |