document.write( "Question 820053: How much 2% acid must be mixed with 10% acid to obtain 2,000 ml of 8% acid? \n" ); document.write( "
Algebra.Com's Answer #493369 by jerryguo41(197)\"\" \"About 
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x=ml of 10% acid in solution
\n" ); document.write( "y=ml of 2% acid in solution\r
\n" ); document.write( "\n" ); document.write( "percentage(amount)+percentage(amount)=total percentage(total amount)
\n" ); document.write( "\".1x%2B.02y=2000%28.08%29\"
\n" ); document.write( "\".1x%2B.02y=160\"
\n" ); document.write( "Substitute \"y=2000-x\"
\n" ); document.write( "\".1x%2B.02%282000-x%29=160\"
\n" ); document.write( "\".1x%2B40-0.02x=160\"
\n" ); document.write( "\"0.08x=120\"
\n" ); document.write( "\"x=1500\"
\n" ); document.write( "--------------
\n" ); document.write( "\"y=2000-x\"
\n" ); document.write( "\"y=2000-1500\"
\n" ); document.write( "\"y=500\"
\n" ); document.write( "--------------
\n" ); document.write( "1500 mL of 10% acid
\n" ); document.write( "500 mL of 2% acid
\n" ); document.write( "creates 2000 mL of 8% acid
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