document.write( "Question 819679: Please help me answer this problem as soon as possible:
\n" ); document.write( "The perimeter of a rectangle is 104 feet. If the width is increased by 3/4 of the length, the width would then be 2 more than the length. Find the original length and width. \n" ); document.write( "
Algebra.Com's Answer #493336 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The perimeter of a rectangle is 104 feet.
\n" ); document.write( " If the width is increased by 3/4 of the length, the width would then be 2 more than the length.
\n" ); document.write( "Find the original length and width.
\n" ); document.write( ":
\n" ); document.write( "2L + 2W = 104
\n" ); document.write( "Simplify divide by 2
\n" ); document.write( "L + W = 52
\n" ); document.write( ":
\n" ); document.write( "\"If the width is increased by 3/4 of the length, the width would then be 2 more than the length.
\n" ); document.write( "W + \"3%2F4\"L = (L+2)
\n" ); document.write( "we can use decimals here
\n" ); document.write( "W + 1.75L = L + 2
\n" ); document.write( "W + 1.75L - L = 2
\n" ); document.write( "W + .75L = 2
\n" ); document.write( ":
\n" ); document.write( "Using elimination
\n" ); document.write( "L + W = 52
\n" ); document.write( ".75L + W = 2
\n" ); document.write( "-------------- subtracting eliminates W, find L
\n" ); document.write( ".25L = 50
\n" ); document.write( "L = 50/.25
\n" ); document.write( "L = 200
\n" ); document.write( "Obviously this can't work\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );