document.write( "Question 811950: 1 + 2^x+1 = 27
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Algebra.Com's Answer #493315 by LinnW(1048) $\"\"$ $\"About$

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revised
\n" ); document.write( " $\"1+%2B+2%5E%28x%2B1%29+=+27\"$
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\n" ); document.write( "\n" ); document.write( "Subtract 1 from each side.
\n" ); document.write( " $\"2%5E%28x%2B1%29+=+26\"$
\n" ); document.write( "So
\n" ); document.write( " $\"log2%2826%29=x%2B1\"$
\n" ); document.write( "This can be computed as $\"log%2826%29%2Flog%282%29=x%2B1\"$
\n" ); document.write( "x+1 = 1.414973/0.3010 = 4.70044
\n" ); document.write( "This makes sense because 2^4 = 16 and 2^5 = 32
\n" ); document.write( "and x = 3.70044
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