document.write( "Question 819906: A truck can travel 315 miles in the same time a car travels 585. If the trucks milage is 30 mph slower than the cars, what is the average rate for each? \n" ); document.write( "
Algebra.Com's Answer #493265 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! You want to find the rate for each. \n" ); document.write( "r= rate for the CAR.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Vehicle__________speed____________time_______________distance \n" ); document.write( "TRUCK____________r-30_____________t__________________315 \n" ); document.write( "CAR______________r________________t__________________518\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using rate*time=distance, get the time expressions for each:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Vehicle__________speed____________time_______________distance \n" ); document.write( "TRUCK____________r-30_____________ \n" ); document.write( "CAR______________r________________ \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remember from description, those times are equal. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The truck goes at 47 mph. \n" ); document.write( " |