document.write( "Question 818780: Given that y=ax^n - 23 and that y=4 when x=3 and y=220 when x=9 find the value of a and n. \n" ); document.write( "
Algebra.Com's Answer #493253 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! Given that y=ax^n - 23 and that y=4 when x=3 and y=220 when x=9 find the value of a and n.\r \n" ); document.write( "\n" ); document.write( "y=ax^n - 23 and that y=4 when x=3 and y=220 when x=9 find the value of a and n.\r \n" ); document.write( "\n" ); document.write( "4 = a(3)^n \n" ); document.write( "and \n" ); document.write( "220 = a(9)^n\r \n" ); document.write( "\n" ); document.write( "Let's solve each equation for a \n" ); document.write( "4 = a(3)^n \n" ); document.write( "divide each side by (3)^n an we have \n" ); document.write( " \n" ); document.write( "Similarly 220 = a(9)^n can be written \n" ); document.write( " \n" ); document.write( "Setting the right hand sides to be equal, \n" ); document.write( " \n" ); document.write( "Taking the cross products we have \n" ); document.write( " \n" ); document.write( "Divide each side by 4 \n" ); document.write( " \n" ); document.write( "Divide each side by \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "Take the log of each side \n" ); document.write( " \n" ); document.write( "Divide each side by log(3) \n" ); document.write( " \n" ); document.write( "Now substitute in \n" ); document.write( "a=0.072727 \n" ); document.write( "Let's check the second equation, 220 = a(9)^n \n" ); document.write( "220 ?= (0.072727)(9^3.647632) \n" ); document.write( "220 ?= (0.072727)(3025.001) \n" ); document.write( " = 219.9992 So considering rounding error we seem to be correct. \n" ); document.write( " |