document.write( "Question 818780: Given that y=ax^n - 23 and that y=4 when x=3 and y=220 when x=9 find the value of a and n. \n" ); document.write( "
Algebra.Com's Answer #493253 by LinnW(1048)\"\" \"About 
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Given that y=ax^n - 23 and that y=4 when x=3 and y=220 when x=9 find the value of a and n.\r
\n" ); document.write( "\n" ); document.write( "y=ax^n - 23 and that y=4 when x=3 and y=220 when x=9 find the value of a and n.\r
\n" ); document.write( "\n" ); document.write( "4 = a(3)^n
\n" ); document.write( "and
\n" ); document.write( "220 = a(9)^n\r
\n" ); document.write( "\n" ); document.write( "Let's solve each equation for a
\n" ); document.write( "4 = a(3)^n
\n" ); document.write( "divide each side by (3)^n an we have
\n" ); document.write( "\"a=4%2F%28%283%29%5En%29\"
\n" ); document.write( "Similarly 220 = a(9)^n can be written
\n" ); document.write( "\"a=220%2F%28%289%29%5En%29\"
\n" ); document.write( "Setting the right hand sides to be equal,
\n" ); document.write( "\"4%2F%28%283%29%5En%29\"=\"220%2F%28%289%29%5En%29\"
\n" ); document.write( "Taking the cross products we have
\n" ); document.write( "\"4%2A%28%289%29%5En%29\"=\"220%2A%28%283%29%5En%29\"
\n" ); document.write( "Divide each side by 4
\n" ); document.write( "\"%28%289%29%5En%29\"=\"%28220%2F4%29%2A%28%283%29%5En%29\"or\"%28%289%29%5En%29\"=\"55%2A%28%283%29%5En%29\"
\n" ); document.write( "Divide each side by \"%28%283%29%5En%29\"
\n" ); document.write( "= \"%28%289%29%5En%29%2F%28%283%29%5En%29\"=\"55\"or \"%28%283%5E2%29%5En%29%2F%28%283%29%5En%29\"=\"55\"
\n" ); document.write( "= \"%28%283%5En%29%5E2%29%2F%28%283%29%5En%29\"=\"55\"So,\"%283%29%5En\"=\"55\"
\n" ); document.write( "Take the log of each side
\n" ); document.write( "\"log%28%283%29%5En%29\"=\"log%2855%29\"so, \"n%2Alog%28%283%29%29\"=\"log%2855%29\"
\n" ); document.write( "Divide each side by log(3)
\n" ); document.write( "\"n\"=\"%28log%2855%29%29%2F%28log%283%29%29\"=3.647632
\n" ); document.write( "Now substitute in \"a=4%2F%28%283%29%5En%29\",\"a=4%2F%28%283%29%5E3.647632%29\",\"a=4%2F%2855%29\"
\n" ); document.write( "a=0.072727
\n" ); document.write( "Let's check the second equation, 220 = a(9)^n
\n" ); document.write( "220 ?= (0.072727)(9^3.647632)
\n" ); document.write( "220 ?= (0.072727)(3025.001)
\n" ); document.write( " = 219.9992 So considering rounding error we seem to be correct.
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