document.write( "Question 819797: The sum of the first 20 terms of an arithmetic sequence is 840. If the common difference is 4, find
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document.write( "(a) The first term
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document.write( "(b) The sum of the first 30 terms \n" );
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Algebra.Com's Answer #493239 by Ms. U(2)![]() ![]() You can put this solution on YOUR website! Formula: S= n/2(2a+(n-1)d) \n" ); document.write( "where \n" ); document.write( "s = sum of progression \n" ); document.write( "n = number of terms \n" ); document.write( "a = value of first term \n" ); document.write( "d = difference between 2 terms or the common difference\r \n" ); document.write( "\n" ); document.write( "(a) \n" ); document.write( "Given: \n" ); document.write( "d= 4 \n" ); document.write( "S(sum of the 20 terms)=840 \n" ); document.write( "n= 20 (because there are 20 terms) \n" ); document.write( "a= ???\r \n" ); document.write( "\n" ); document.write( "Substitute the given value. \n" ); document.write( "840 = 20/2[2a+(20-1)4] \n" ); document.write( "840 = 10[2a+ (19)4] \n" ); document.write( "840 = 10 (2a + 76) *Distribute 10 in(2a + 76)* \n" ); document.write( "840 = 20a + 760 *Transpose 760 to the left side of the equal sign. \n" ); document.write( "840 - 760 = 20a \n" ); document.write( "80 = 20a * Divide both sides by 20. \n" ); document.write( "80/20 = 20a/20 \n" ); document.write( "a= 4 \r \n" ); document.write( "\n" ); document.write( "The first term is 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(b) \n" ); document.write( "a= 4 \n" ); document.write( "d= 4 \n" ); document.write( "n= 30 \n" ); document.write( "S(sum of the 30 terms)=???\r \n" ); document.write( "\n" ); document.write( "S= 30/2 [2(4)+ (30-1)4] \n" ); document.write( "S= 15 [8 + (29)4] \n" ); document.write( "S= 15 [8 + 116] \n" ); document.write( "S= 15 (124) \n" ); document.write( "S= 1860\r \n" ); document.write( "\n" ); document.write( "The sum of the first 30 terms is 1860. \n" ); document.write( " |