document.write( "Question 819797: The sum of the first 20 terms of an arithmetic sequence is 840. If the common difference is 4, find
\n" ); document.write( "(a) The first term
\n" ); document.write( "(b) The sum of the first 30 terms
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Algebra.Com's Answer #493239 by Ms. U(2)\"\" \"About 
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Formula: S= n/2(2a+(n-1)d)
\n" ); document.write( "where
\n" ); document.write( "s = sum of progression
\n" ); document.write( "n = number of terms
\n" ); document.write( "a = value of first term
\n" ); document.write( "d = difference between 2 terms or the common difference\r
\n" ); document.write( "\n" ); document.write( "(a)
\n" ); document.write( "Given:
\n" ); document.write( "d= 4
\n" ); document.write( "S(sum of the 20 terms)=840
\n" ); document.write( "n= 20 (because there are 20 terms)
\n" ); document.write( "a= ???\r
\n" ); document.write( "\n" ); document.write( "Substitute the given value.
\n" ); document.write( "840 = 20/2[2a+(20-1)4]
\n" ); document.write( "840 = 10[2a+ (19)4]
\n" ); document.write( "840 = 10 (2a + 76) *Distribute 10 in(2a + 76)*
\n" ); document.write( "840 = 20a + 760 *Transpose 760 to the left side of the equal sign.
\n" ); document.write( "840 - 760 = 20a
\n" ); document.write( "80 = 20a * Divide both sides by 20.
\n" ); document.write( "80/20 = 20a/20
\n" ); document.write( "a= 4 \r
\n" ); document.write( "\n" ); document.write( "The first term is 4.\r
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\n" ); document.write( "\n" ); document.write( "(b)
\n" ); document.write( "a= 4
\n" ); document.write( "d= 4
\n" ); document.write( "n= 30
\n" ); document.write( "S(sum of the 30 terms)=???\r
\n" ); document.write( "\n" ); document.write( "S= 30/2 [2(4)+ (30-1)4]
\n" ); document.write( "S= 15 [8 + (29)4]
\n" ); document.write( "S= 15 [8 + 116]
\n" ); document.write( "S= 15 (124)
\n" ); document.write( "S= 1860\r
\n" ); document.write( "\n" ); document.write( "The sum of the first 30 terms is 1860.
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