document.write( "Question 819749: How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze? (Hint: Let x represent the number of gallons of 65% antifreeze. Then 50 - x represents the amount of 20% antifreeze.)
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Algebra.Com's Answer #493229 by TimothyLamb(4379)\"\" \"About 
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65s + 20w = 56(50)
\n" ); document.write( "s + w = 50
\n" ); document.write( "w = 50 - s
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\n" ); document.write( "65s + 20w = 56(50)
\n" ); document.write( "65s + 20(50 - s) = 2800
\n" ); document.write( "65s + 1000 - 20s = 2800
\n" ); document.write( "45s = 1800
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\n" ); document.write( "s = 40 gal
\n" ); document.write( "w = 10 gal
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