document.write( "Question 69251: Solve by completing the square.\r
\n" ); document.write( "\n" ); document.write( "4x^2 = 2x - 3 = 0\r
\n" ); document.write( "\n" ); document.write( "I have worked this problem three times now and can not figure it out. Could somebody please help me????? \n" ); document.write( "
Algebra.Com's Answer #49321 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Solve by completing the square.
\n" ); document.write( "Assume that the 1st \"=\" sign should be +
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\n" ); document.write( "Having 4 as the coefficient of x^2 does complicate matters, however...
\n" ); document.write( "4x^2 + 2x - 3 = 0
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\n" ); document.write( "4x^2 + 2x = + 3
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\n" ); document.write( "Make the coefficient of x^2 one, divide equation by 4
\n" ); document.write( "x^2 + (2/4)x __ = 3/4
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\n" ); document.write( "x^2 + (1/2)x __ = 3/4
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\n" ); document.write( "Choose a value that completes the square: (1/2)(1/2) =(1/4)^2 = 1/16
\n" ); document.write( "x^2 + (1/2)x + (1/16) = (3/4) + (1/16)
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\n" ); document.write( "x^2 + (1/2)x + (1/16) = (12/16) + (1/16)
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\n" ); document.write( "x^2 + (1/2)x + (1/16) = 13/16
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\n" ); document.write( "[x + (1/4)]^2 = 13/16
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\n" ); document.write( " x + (1/4) = +/-Sqrt(13/16)
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\n" ); document.write( "The denominator (16) is a square, extract that (1/4)
\n" ); document.write( "x + (1/4) = +/-(1/4)Sqrt(13)
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\n" ); document.write( "x = -(1/4) +/-(1/4)Sqrt(13)
\n" ); document.write( "or
\n" ); document.write( "x = \"%28%28-1+%2B+Sqrt%2813%29%29%29%2F4\"
\n" ); document.write( "and
\n" ); document.write( "x = \"%28%28-1+-+Sqrt%2813%29%29%29%2F4\"
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\n" ); document.write( "Did this help?
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