document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=819699>Question 819699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a number, one third of that number, and one fourth of that number are added. the result is 57. what is the original number ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #493183 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=493183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let number be x\r<BR>\n" );
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document.write( "x+x/3 +x/4 = =57\r<BR>\n" );
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document.write( "multiply the equation by 12\r<BR>\n" );
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document.write( "12x+4x+3x=12*57\r<BR>\n" );
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document.write( "19x=12*57\r<BR>\n" );
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document.write( "x=12*57/19\r<BR>\n" );
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document.write( "x=36 </SPAN>\n" );
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