document.write( "Question 819561: The perimeter of a rectangle is 64 inches. The width is 8 inches longer than the size of the length. What are the dimensions of rectangle?
\n" ); document.write( "We think the length is 12 and the width is 20 but we aren't sure how to write it as an equation.
\n" ); document.write( "Thank you
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Algebra.Com's Answer #493145 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let L = length, W = width\r
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\n" ); document.write( "\n" ); document.write( "\"The width is 8 inches longer than the size of the length\" ----> \"W+=+L%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"The perimeter of a rectangle is 64 inches\" means that \"P=2L%2B2W\" turns into \"64=2L%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "\"64=2L%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "\"64=2L%2B2%28L%2B8%29\" Plug in W = L+8 (ie replace W with L+8)\r
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\n" ); document.write( "\n" ); document.write( "\"64=2L%2B2L%2B16\"\r
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\n" ); document.write( "\n" ); document.write( "\"64=4L%2B16\"\r
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\n" ); document.write( "\n" ); document.write( "\"64-16=4L\"\r
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\n" ); document.write( "\n" ); document.write( "\"48=4L\"\r
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\n" ); document.write( "\n" ); document.write( "\"4L=48\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=48%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=12\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+L%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+12%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+20\"\r
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\n" ); document.write( "\n" ); document.write( "So the width is 20 inches and the length is 12 inches.\r
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